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Involves polygon sides.
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I must be a beast because I added up all the vertices from left to right and got 17, 15, so the last row had to equal 13 to keep the pattern going so, we needed a three sided figure to get 13. Going to go back and learn the minus thing everyone is talking about.
Also my way is sketchy, because I miscounted row one and got it wrong- but my ideology was correct.
No. of sides from first columns shapes are getting minus from second columns shape so row wise its like below...
7-4 = 3
6-3 = 3 so shape with three sides will come
I just saw that each time for Ma and Tr the number of sides went down by one but Ix stayed the same.
The way I found it was by subtracting the amount of sides in the shape in the 1st and 2nd columns.
E. In every row, the sides of the left polygon is equal to the sides of the remaining two polygons.
Alternative solution, (sequence): The total polygon sides in first row is 16, second row 14, and third row 12.
The totals are 17, 15, 13,
I had miscounted as well.